The following is the piece of code, it takes a string and outputs the characters that have repeated with corresponding frequency. The code given below is compiled and tested.
//Import the header files #include<stdio.h> #include<conio.h> #include<string.h> //Main function main(){ //Variables initialization int i=0,j,k=0,m=0,f=0,len,count=0; char ch,aj[30],r[30]; //Read the string printf("Enter the string:\n"); while(1){ scanf("%c",&ch); if(ch=='e'){ break; } aj[i++]=ch; } //print the enetered string len=strlen(aj); for(i=0;i<len;i++){ printf("%c",aj[i]); } //A brute force algorithm for(i=0;i<len;i++){ for(j=i+1;j<len;j++){ if(aj[i]==aj[j]){ for(m=0;m<strlen(r);m++){ if(aj[i]==r[m]){ f=1; } } if(f==0){ r[k]=aj[i]; k++; } else{ break; } } } } //print the results printf("Characters that repeat are:\n"); for(i=0;i<strlen(r);i++){ count=0; for(m=0;m<len;m++){ if(r[i]==aj[m]){ count++; } } //Print the stats printf("Character\t %c\t Frequency\t %d\n",r[i],count); } }